Multiple Passwords

[NotPythonQueen]

Because x in thisdict checks against the keys of the dictionary (1, 2, and 3). You would have to check x in thisdict.values(). Note that checking against the keys is very fast in Python, but checking against the values is probably a bit slower than using a list.

okay i will use it like this, but it still didn't work

thisdict = {
  "sport": "football",
  "drink": "sprite",
  "food": "pizza"
} 
password = input("Please enter a password: ")
if password x in thisdict.values()
    print("Welcome!")