Сheck if an element from a list is in another list that contains a namedtuple

[deanhystad]

Don't remove, append. I would build a new list that only contains the requirements you want to keep, and I would use set operations to determine which requirements to save

from collections import namedtuple
from random import randint

Import = namedtuple("Import", ("module", "name", "alias"))

files = set(range(100, 200))

# All the requirements
requirements = [Import(randint(1, 1000), randint(1, 1000), randint(1, 1000)) for _ in range(10)]

# Requirements that have no match with any file.
requirements = [req for req in requirements if set(req).isdisjoint(files)]
print(*requirements, sep="\n")