Facing Problem while opening a file through command prompt - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: Facing Problem while opening a file through command prompt (/thread-36223.html) |
Facing Problem while opening a file through command prompt - vlearner - Jan-29-2022 Hi Everyone, Here is the code that I have written for reading a file through command prompt. from sys import argv script, filename = argv txt = open(filename) print(f"Here's your file {filename}:") print(txt.read()) print("Type the filename again:") file_again = input("> ") txt_again = open(file_again) print(txt_again.read())but while executing this program I am facing this error please guide me through this problem
RE: Facing Problem while opening a file through command prompt - Larz60+ - Jan-29-2022 When I try this it works fine. Note: every line in your script (except first) is indented 1 space. This might be the reason you are having problems. Also, since argv is a list, you can use filename = argv[1] to get the second argument. RE: Facing Problem while opening a file through command prompt - BashBedlam - Jan-29-2022 The error is being generated by code other than what you uploaded. txt = open(file.txt)
RE: Facing Problem while opening a file through command prompt - vlearner - Jan-30-2022 (Jan-29-2022, 03:03 PM)Larz60+ Wrote: When I try this it works fine.I tried this way but it is showing list index out of range. RE: Facing Problem while opening a file through command prompt - snippsat - Jan-30-2022 # fs.py from sys import argv script, filename = argv txt = open(filename) print(f"Here's your file {filename}:") print(txt.read()) print("Type the filename again:") file_again = input("> ") txt_again = open(file_again) print(txt_again.read())From command line i have two files in bar folder your code fs.py and test.txt . As you see the code is working.
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